Boyce-Codd Normal Form (BCNF)
Rules for BCNF
For a table to satisfy the Boyce-Codd Normal Form, it should satisfy the following two conditions:
- It should be in the Third Normal Form.
- And, for any dependency A → B, A should be a super key.
The second point sounds a bit tricky, right? In simple words, it means, that for a dependency A → B, A cannot be a non-prime attribute, if B is a prime attribute.
Below we have a college enrolment table with columns student_id, subject and professor.
As you can see, we have also added some sample data to the table.
In the table above:
- One student can enrol for multiple subjects. For example, student with student_id101, has opted for subjects – Java & C++
- For each subject, a professor is assigned to the student.
- And, there can be multiple professors teaching one subject like we have for Java.
What do you think should be the Primary Key?
Well, in the table above student_id, subject together form the primary key, because using student_id and subject, we can find all the columns of the table.
One more important point to note here is, one professor teaches only one subject, but one subject may have two different professors.
Hence, there is a dependency between subject and professor here, where subject depends on the professor name.
This table satisfies the 1st Normal form because all the values are atomic, column names are unique and all the values stored in a particular column are of same domain.
This table also satisfies the 2nd Normal Form as their is no Partial Dependency.
And, there is no Transitive Dependency, hence the table also satisfies the 3rd Normal Form.
But this table is not in Boyce-Codd Normal Form.
Why this table is not in BCNF?
In the table above, student_id, subject form primary key, which means subject column is a prime attribute.
But, there is one more dependency, professor → subject.
And while subject is a prime attribute, professor is a non-prime attribute, which is not allowed by BCNF.
How to satisfy BCNF?
To make this relation(table) satisfy BCNF, we will decompose this table into two tables, student table and professor table.
Below we have the structure for both the tables.
|and so on…|
And, Professor Table
|and so on…|